Recent comments

Reply to: LibRaw::subtract_black()   5 years 11 months ago

It operates on raw data populated into image[]

raw_image[] is always untouched (to allow processing of same data multiple times w/o calling unpack())

Reply to: Processing image From Fujitsu X-T3   5 years 11 months ago

There are several interpolation options for X-Trans (from fastest to slowest):
- half
- bilinear
- single pass Markesteijn
- 3-pass Markesteijn

Reply to: Convert to Tiff so That it looks as close to raw preview as possible?   5 years 11 months ago

Sorry, there is no such function in LibRaw.

To match vendor (out-of camera JPEG) colors one needs to use same (vendor) color profile data and same contrast (tonal) curve. Tonal curve, in turn, is settings-specific.

Reply to: Copyright for LibRaw needs update   5 years 11 months ago

In what file?

Reply to: Problems with certain DNGs - strong color casts   5 years 11 months ago

Could you please provide file for analysis (Dropbox/Google Drive/etc link...)

Reply to: Windows VS2017 OpenMP   5 years 11 months ago

LibRaw uses OpenMP for postprocessing (there is single exception: Fuji compressed decompression is also OpenMP-capable).

AFAIK, you do own postprocessing. So, for most files (see exception above) enabling OpenMP for LibRaw will change nothing.

If your code is OpenMP-enabled, it is up to you what settings to use.

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

Depending on the offset of the active zone, camera model (obviously), and firmware - useful Bayer patterns can be different. Answering pattern questions, specific to model, firmware, or active zone, makes sense only if there is a bug in the library, and only with a "thank you!".

From LibRaw docs:

unsigned black;
Black level. Depending on the camera, it may be zero (this means that black has been subtracted at the unpacking stage or by the camera itself), calculated at the unpacking stage, read from the RAW file, or hardcoded.

my comment: if only one black level value is found / hardcoded / calculated, it is in this field. Before using it, you may want to check the content of cblack.

More from docs:
unsigned cblack[4102];
Per-channel black level correction. First 4 values are per-channel correction, next two are black level pattern block size, than cblack[4]*cblack[5] correction values (for indexes [6....6+cblack[4]*cblack[5]).

my comment: if 4 (per channel) black level values are found / calculated from sources other than Adobe EXIF tag (with one exception that is irrelevant for the matter at hand), for the camera you are interested in they are read into cblack[0 .. 3] in 0 1 3 2 index order (see code, permutations
FORC4 cblack[c ^ c >> 1] = get2();
do that. That's the way Mr. Coffin did it in dcraw, and we preserved it in LibRaw for compatibility.)

if cblack[0] is 0, and / or cblack[4 .. 5] are present (DNG), you can use cblack [6 .. ...]. You can follow the code under "case 0xc61a" to see the order cblack is populated in this case. For a regular DNG, the cycle in essence is
FORC(cblack[4] * cblack[5]) cblack[6+c] = getreal(type);
meaning, the order coming from Adobe EXIF tag is preserved. Again, preserved from dcraw for compatibility.

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

Thank you

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

The CFA for the K5 is BGGR format (silly me for assuming RGGB). So I think the coefficients in cblack[6-9] are in that order. Is the order for cblack[0-3] RGGB - if so that explains the reversal I see - or am I still confused??

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

I believe that it tells me the order in the DNG file is RGGB (if I read it right) and this this maps directly into cblack[6-9]. It doesn't confirm the order for cblack[0-3] In fact I'm not even sure now about that order given what I see in the cblack array before and after calling adjust_bl() as per my post on 24 June, 2019 - 15:39 which I repeat the data of here:

00000094 2019/06/24 14:33:18.354 018788 00002900             >Before adjust_bl() C.black = 0.
00000095 2019/06/24 14:33:18.363 018788 00002900             >First 10 C.cblack elements
00000095 2019/06/24 14:33:18.363 018788 00002900             >0, 0, 0, 0
00000095 2019/06/24 14:33:18.363 018788 00002900             >2, 2
00000095 2019/06/24 14:33:18.363 018788 00002900             >513, 513, 515, 516
00000096 2019/06/24 14:33:18.372 018788 00002900             >Subtracting black level of C.black = 513 from raw_image data.
00000097 2019/06/24 14:33:18.382 018788 00002900             >First 10 C.cblack elements
00000097 2019/06/24 14:33:18.382 018788 00002900             >516, 515, 513, 513
00000097 2019/06/24 14:33:18.382 018788 00002900             >0, 0
00000097 2019/06/24 14:33:18.382 018788 00002900             >513, 513, 515, 516

should I expect the order of cblack[0]-cblack[3] to be the reverse of cblack[6]-cblack[9]???

If I'm not understanding what's going on here please correct my misunderstandings

David

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

(edited to remove flame - ib)
yes I did look at the code, but you could have maybe said something like:

Yes the order is different (or not), as you will see if you compare the processing for DNG black level at case xxxxx and the one for Black Point at case yyyyy

And then pointed me at the DNG spec to add more information. I still don't know for certain that cblack[0-3] is in a different order to cblack[6-9]

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

Dear Sir:

Quoting Adobe again, from a previous, "The origin of this pattern is the top-left corner of the ActiveArea rectangle. The values are stored in row-column-sample scan order". How do you interpret this? Please draw two different Bayer patterns and suggest how the tag should be filled based on the description above.

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

Dear Sir:

Have you already looked at processing of pertinent EXIF tags under "case 0xc619" and "case 0xc61a"? They simply read the EXIF tags, and thus my reference to Adobe DNG Specification is quite justified. Please read Adobe documentation and try to understand it.

I don't see the reason for your anger, but in any case please refrain from showing it here in future.

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

Well, actually I am asking about the color.cblack array provided by YOU to my application.

Clearly you think you're justified in saying that isn't something you answer questions on.

If I gave answers like that to my customers when I was providing tech support I would have been fired (quite rightly) by my management.

D.

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

Dear Sir:

In my previous post I quoted Adobe documentation on the matter. I'm afraid you are not paying attention. Your question is about EXIF, not LibRaw.

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

You know the purpose of documentation is so other people can read use and understand your stuff. It's no great surprise that you understand it!

You still didn't answer my question about the order of values in cblack[0-3] versus cblack[6-9]. I *think* that it is RGBG for cblack[0-4] and RGGB for cblack[6-9].

Of course if you had deigned to answer my questions in the first place instead of almost going out of your way to avoid doing so - saying along the way "Well I understand it ..." that would have saved me a lot of time which is what this forum is supposed to be about.

Reply to: LibRaw 0.20 supported cameras   5 years 11 months ago

Dear Sir:

I think the place to ask is https://chdk.fandom.com/wiki/CHDK

Reply to: LibRaw 0.20 supported cameras   5 years 11 months ago

PowerShot SX20 IS (CHDK hack)

Please advise what settings to use with CHDK hack, etc. in order for this to work properly.
Thank You!

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

Dear Sir:
I don't find the description lacking.
For parsing cblack in DNG and for order used in EXIF tags please see DNG specification: "This tag specifies the zero light ... encoding level, as a repeating pattern. The origin of this pattern is the top-left corner of the ActiveArea rectangle. The values are stored in row-column-sample scan order."
Reading DNG specification may help answering your questions.
For DNG, cblack is filled under "case 0xc619" in parse_tiff_ifd.

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

Still seeking clarification here ... What order are the first four cblack elements in? RGBG, RGGB?

What order they in for cblack[6]-[9]?

What order are they supposed to be in for the exif tags?

Is there any clear write up explaining the cblack value array other than the code and the rather terse decription in the documentation which doesn't explain much ...?

Thanks

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

I'm now using adjust_bl() before doing my black level subtraction, and I'm seeing:

00000094 2019/06/24 14:33:18.354 018788 00002900             >Before adjust_bl() C.black = 0.
00000095 2019/06/24 14:33:18.363 018788 00002900             >First 10 C.cblack elements
00000095 2019/06/24 14:33:18.363 018788 00002900             >0, 0, 0, 0
00000095 2019/06/24 14:33:18.363 018788 00002900             >2, 2
00000095 2019/06/24 14:33:18.363 018788 00002900             >513, 513, 515, 516
00000096 2019/06/24 14:33:18.372 018788 00002900             >Subtracting black level of C.black = 513 from raw_image data.
00000097 2019/06/24 14:33:18.382 018788 00002900             >First 10 C.cblack elements
00000097 2019/06/24 14:33:18.382 018788 00002900             >516, 515, 513, 513
00000097 2019/06/24 14:33:18.382 018788 00002900             >0, 0
00000097 2019/06/24 14:33:18.382 018788 00002900             >513, 513, 515, 516

should I expect the order of cblack[0]-cblack[4] to be the reverse of cblack[7]-cblack[9]???

I'd have expected it to be in the same order as the levels reported by exiftool (513, 513, 515, 516)

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

> I'd much appreciate some explanation of how cblack really works and how I should process these when operating on the raw image data?

You also didn't address that at all.

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

However variable black is ZERO and I don't believe it should be

Reply to: Problem with dng file from Pentax K5-II   5 years 11 months ago

Not 0,
513, 513, 515, 516

Reply to: What to do with rgb_cam matrix   5 years 11 months ago

I understand that you may be feeling "got at" here, but to be fair the OP does have a point in that the code definitely does suffer from a distinct paucity of comments - and while you say the libraw focus is on extracting data from raw files, there's still a very high proportion of the code dedicated to post-processing the raw image.

I truly don't expect you to drop everything and add reams of comments but if the next time you go near any code that lacks comments, adding some lines to explain how/why it's doing what it does would be most helpful to the rest of us.

Cheers

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