LibRaw::subtract_black()

Submitted by David Partridge on

Documentation page says it operates on the raw image, but AFAICT it operates on image[0], rather than rawdata.raw_image.

Or does rawdata.raw_image actually point to image[0]???

Thanks

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It operates on raw data

Submitted by lexa on

It operates on raw data populated into image[]

raw_image[] is always untouched (to allow processing of same data multiple times w/o calling unpack())

-- Alex Tutubalin @LibRaw LLC