Ummm, let's me think about Ummm, let's me think about that... RFC[] are calculate using: (for 3 images, sorted by exposition, lower exposition first, and so ... ) RFC[0]= 1.0 always RFC[1]= SUM_A / SUM_B * RFC[0] RFC[2]= SUM_B / SUM_C * RFC[1] SUM_A is R,G1 and B from image 0 SUM_B is the same from image 1 SUM_C is the same from image 2 Then this must be refact so RFC[0] + RFC[1] + RFC[0] = 1.0 ? reply
Ummm, let's me think about that...
RFC[] are calculate using: (for 3 images, sorted by exposition, lower exposition first, and so ... )
RFC[0]= 1.0 always
RFC[1]= SUM_A / SUM_B * RFC[0]
RFC[2]= SUM_B / SUM_C * RFC[1]
SUM_A is R,G1 and B from image 0
SUM_B is the same from image 1
SUM_C is the same from image 2
Then this must be refact so RFC[0] + RFC[1] + RFC[0] = 1.0 ?